The the circle passing through the foci of the $\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{9} = 1$ and having centre at $(0,3) $ is
The the circle passing through the foci of the $\frac{{{x^2}}}{{16}} + \frac{{{y^2}}}{9} = 1$ and having centre at $(0,3) $ is
- [JEE MAIN 2013]
- A
${x^2} + {y^2} - 6y - 7 = 0$
- B
$\;{x^2} + {y^2} - 6y + 7 = 0$
- C
$\;{x^2} + {y^2} - 6y - 5 = 0$
- D
$\;{x^2} + {y^2} - 6y + 5 = 0$
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